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ChopEqvChop
⊢
f
≡
f
1
,
⊢
g
≡
g
1
⇒ ⊢
f
;
g
≡
f
1
;
g
1
ChopEqvChop
Proof:
1
⊢
f
≡
f
1
given
2
⊢
f
;
g
≡
f
1
;
g
1
,
LeftChopEqvChop
3
⊢
g
≡
g
1
given
4
⊢
f
1
;
g
≡
f
1
;
g
1
3
,
RightChopEqvChop
5
⊢
f
;
g
≡
f
1
;
g
1
2
,
4
,
EqvChain
qed
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2023-09-12
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