BoxImpBoxRule

f g ⇒ ⊢ f g BoxImpBoxRule

Proof:

1
f g
given
2
⊢ ¬g ⊃¬f
1,Prop
3
(¬g ⊃ ¬f)
4
(¬g ⊃ ¬f) (true ; ¬g) (true ; ¬f)
5
true ; ¬g true ; ¬f
3, 4,MP
6
¬g ¬f
5, def. of 
7
⊢ ¬¬f ⊃¬¬g
6,Prop
8
f g
7, def. of 

qed

2023-09-12
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