ChopLoop

f g ; f, g more ⇒ ¬f ChopLoop

Proof:

1
f g ; f
given
2
g more
given
3
g ; f more ; f
4
f more ; f
1, 3,ImpChain
5
⊢ ¬f

qed

Here is a variant of lemma MoreChopContra that is useful in proofs:

2023-09-12
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